2xy=x^2+3y^2-12

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Solution for 2xy=x^2+3y^2-12 equation: 


Simplifying
2xy = x2 + 3y2 + -12

Reorder the terms:
2xy = -12 + x2 + 3y2

Solving
2xy = -12 + x2 + 3y2

Solving for variable 'x'.

Reorder the terms:
12 + 2xy + -1x2 + -3y2 = -12 + x2 + 3y2 + 12 + -1x2 + -3y2

Reorder the terms:
12 + 2xy + -1x2 + -3y2 = -12 + 12 + x2 + -1x2 + 3y2 + -3y2

Combine like terms: -12 + 12 = 0
12 + 2xy + -1x2 + -3y2 = 0 + x2 + -1x2 + 3y2 + -3y2
12 + 2xy + -1x2 + -3y2 = x2 + -1x2 + 3y2 + -3y2

Combine like terms: x2 + -1x2 = 0
12 + 2xy + -1x2 + -3y2 = 0 + 3y2 + -3y2
12 + 2xy + -1x2 + -3y2 = 3y2 + -3y2

Combine like terms: 3y2 + -3y2 = 0
12 + 2xy + -1x2 + -3y2 = 0

The solution to this equation could not be determined.

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